Question

1=2 solve it if you can ​

Answer 1

Answer:

It cannot be solved

Step-by-step explanation:

As

1 is not equal to 2

1 + 1 = 2

=> 2 = 2

$<svg width="25" height="230" viewBox="0 0 100 100">\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <path fill="PURPLE" d="M92.71,7.27L92.71,7.27c-9.71-9.69-25.46-9.69-35.18,0L50,14.79l-7.54-7.52C32.75-2.42,17-2.42,7.29,7.27v0 c-9.71,9.69-9.71,25.41,0,35.1L50,85l42.71-42.63C102.43,32.68,102.43,16.96,92.71,7.27z"></path>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ <animateTransform \ \textless \ br /\ \textgreater \ attributeName="transform" \ \textless \ br /\ \textgreater \ type="scale" \ \textless \ br /\ \textgreater \ values="1; 1.5; 1.25; 1.5; 1.5; 1;" \ \textless \ br /\ \textgreater \ dur="2s" \ \textless \ br /\ \textgreater \ repeatCount="40"> \ \textless \ br /\ \textgreater \ </animateTransform>\ \textless \ br /\ \textgreater \ \ \textless \ br /\ \textgreater \ </svg>$

Answer 2

Step-by-step explanation:

If

$x = y$

multiply both sides by x

${x}^{2} = xy \\ {x}^{2} - {y}^{2} = xy - {y}^{2} \\ (x + y)(x - y) = y(x - y)$

we can cancel (x-y)

$x + y = y \\ x + x = x \\ 2x = x \\ 2 = 1$

y=x can be put in y.