Question

1
2 tan 0 sec
1
b.
h.
1-sin e 1 + sin e
cos A + sin A
cos A-sin A
1 + tan A
1 -tan A
d.
i.
f.
a
2.
1 - sin a cos a
h.
1 - cos e
= cosec 0 - coto
1 + cos e
sin’a + cos'a
sin a + cos a
1-sin x
(sec X - tan x)?
1 + sin x
.
j.
1 + sin 0/1 - sin e
1 +
+ cos 0) (1 - cos
1 - sin & -cose
1.
sin20
+ sec a)​

Answer 1

Answer:

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