Question

1
= 2 x 2 x2,
16 = 2 x 2 x 2 x 2,
60'= 2x2x2x3.
The HCF of 8, 16 and 24 is 2x2x2 = 8.
The required number is answer = 8.
EXERCISE 6.1
ind the HCF of the numbers by inspection :
(d) 40 and 70
a) 4 and 12
(c) 36 and 54
(b) 18 and 24
(h) 32 and 72
(g) 12 and 54
(f) 51 and 85
e) 24 and 60
(1) 15 and
(k) 23 and 12
(1) 19 and 27
13 and 15
e
ind the HCF of the numbers by finding factors :
(d) 60,55
(c) 24, 36
3. 9
(b) 20,45​

Answer 1

Answer❣

Given

Perimeter of Rectangle is 60m

length is 4m more than four times it's breadth

To Find

length and breadth of the Rectangle

Solution

Let us assume the breadth of Rectangle be 'x'

according to the question

length would be => 4m+4x

Perimeter is 60m

Perimeter of Rectangle=2(length+Breadth)

=>60= 2( 4+4x +x)

=>60=2(4+5x)

=>2(4+5x)=60

=>4+5x=30

=>5x= 30-4

=>5x= 26

=>x= 26÷ 5

=>x=5.2

Now , breadth is 5.2m

length = 4+4x=4+4×5.2

length= 4+20.8=24.8m

Check

Perimeter of Rectangle=2( 24.8+5.2)

Perimeter of Rectangle=2(30)

Perimeter of Rectangle= 60m

Extra information=>

Perimeter is the total distance occupy by a solid 2D figure around its edge.

Area of Rectangle= length × breadth

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