Question

(1/2 x+3/2 y)^2 expand
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Answer 1

Answer: $\frac{1x^2}{4} + \frac{3xy}{2} + \frac{9y^2}{4}$

Step-by-step explanation:

We can use the identity : $(a+b)^{2}$ = $a^{2} + 2ab + b^{2}$

So, $(\frac{1}{2}x + \frac{3}{2}y ) = (\frac{1}{2}x)^{2} + 2(\frac{1}{2}x)(\frac{3}{2}y )$ + $(\frac{3}{2}y )^{2}$

                      ⇒$\frac{1x^2}{4} + \frac{3xy}{2} + \frac{9y^2}{4}$

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Answer 2

Answer:

thaaaaaankuu for answering buddy