Question

1/2 [X+Z-5] =y-Z = 2x-11=9-[x+2x]​

Answer 1

Answer:

Simplify each term.

1 2 ⋅ ( X + Z − 5 ) = 9 − 3 x

Step-by-step explanation:

Answer 2

Form a quadratic equation whose Roots are x,y,zx,y,z

Now, let the equation be ax3+bx2+cx+d=0ax3+bx2+cx+d=0

So, Sumx+y+z=−b/ax+y+z=−b/a

xy+yz+xz=c/axy+yz+xz=c/a

xyz=−d/axyz=−d/a

If a=1a=1, equation will be x3−6x2+15x−14=0x3−6x2+15x−14=0

So,x=2x=2 is a root of equation : the equation can be written as (x−2)(x2−4x+7)=0(x−2)(x2−4x+7)=0

Since x2−4x+7=0x2−4x+7=0 has imaginary roots which are 2+isqrt32+isqrt3 and 2−isqrt32−isqrt3

So, the only real solution for this equation is x=2x=2

Hope this was helpful.

Regards.