Question

1/2(xsquare-x)-1/4(x-3+3x square)​

Answer 1

Answer:

$\huge\bigstar\huge\tt\underline\red{ᴀɴsᴡᴇʀ }\bigstar$

Here is your answer

$\frac{1}{2} ( {x}^{2} - x) - \frac{1}{4} (x - 3 + 3 {x}^{2} )$

$\frac{2 {x}^{2} - 2x - x + 3 - 3 {x}^{2} }{4} = 0$

$- {x}^{2} - 3x + 3 = 0$

${x}^{2} + 3x - 3 = 0$

see the image above attach for complete solution step by step:-

we use quadratic formula to find out the value of x:

Hope it helps you..!!!

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Thankyou:)

Answer 2

Here is your answer\frac{1}{2} ( {x}^{2} - x) - \frac{1}{4} (x - 3 + 3 {x}^{2} ) 21 (x 2 −x)− 41 (x−3+3x 2 )\frac{2 {x}^{2} - 2x - x + 3 - 3 {x}^{2} }{4} = 0 42x 2 −2x−x+3−3x 2 =0- {x}^{2} - 3x + 3 = 0−x 2 −3x+3=0{x}^{2} + 3x - 3 = 0x 2 +3x−3=0