Question

1
/2
[y – (2y + 2) ] = 5[y + 1]​

Answer 1

Answer:

y = -1.2

Step-by-step explanation:

1/2[y - (2y + 2)] = 5[y + 1]

=> 1/2[y - 2y + y - 2)] = 5y + 5

=> 1/2[- 2] = 5y + 5

=> -2/2 = 5y + 5

=> -1 = 5y + 5

=> -1 - 5 = 5y

=> -6 = 5y

=> -6/5 = y

=> -1.2 = y

=> y = -1.2