Question

1.2 y 3.
If the average of 6, 11, 19 and lies between 19 and'd' (19<d), which of
he following is true?
B. d = 40 C.d > 40
D. None​

Answer 1

COMPLETE QUESTION

If the average of 6, 11, 19 and 'd' lies between 19 and'd' (19<d), which of

he following is true?

B. d = 40

C.d > 40

D. None

ANSWER

Option (C) D > 40 Is True.

GIVEN

Data = 6, 11, 19, 'd'

value of d is greater than 19.

Average of the given value lies between 19 and 'd'

TO FIND

which option is correct.

SOLUTION

We can simply solve the above problem as follows-

Average is the sum of all values divided by number or values -

$Average, A = \frac{6 + 11 + 19 + d}{4}$

It is given that,

The average lies between 19 and d

That is, Value of A is greater than 19 and smaller than 'd'.

If we take, d = 40

So,

$A = \frac{6 + 11 + 19 + 40}{4} = 19$

A = 19

this does not satisfy with the given condition.

So, option B is False.

If we take, d > 40

Let, d = 41

so,

$A = \frac{6 + 11 + 19 + 41}{4} = 19.25$

This satisfies the condition.

So if we take any number greater than 40 as 'd', the average will lie between 19 and d.

Hence, option (c) d > 40 is True.

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