1. 20 men and 25 women together can complete a work in 5 days. It takes 150 days for one man
alone to complete the work. How many days will be required for one woman to complete the
same work?
A) 300 B) 325 C) 350 D) 375
Answers
Answer:
According to question:-
5(20M+25W)=1M×150
100M+125W=150M
125W=150M-100M
125W=50M
5W=2M
1 men can do the work in 150 days.
2 men can do the work in 150/2 =75 days.
No. of days by women=75×5
=375 days.
Hence , option d is correct.
Given : 20 men and 25 women together can complete a work in 5 days.
It takes 150 days for one man alone to complete the work.
To Find : How many days will be required for one woman to complete the
same work?
Solution:
20 men and 25 women together can complete a work in 5 days.
=> Total work = 20 * 5 man days + 25* 5 woman days
= 100 Man days + 125 woman days
It takes 150 days for one man alone to complete the work.
=> Total Work = 150 Man days
100 Man days + 125 woman days = 150 Man days
=> 125 woman days = 50 Man days
Multiplying by 3 both sides
=> 375 woman days = 150 Man days
Total Work = 150 Man days = 375 woman days
Hence 375 days will be required for one woman to complete the
same work
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