Question

1
20.The mass defect for an
isotope was found to be 0.410
amulatom. Calculate the
binding energy in kJ/mol of
atoms. (1 J = 1 kgm2/s2)
O 3.69 x 1010 kJ/mol
O O O
O 1.23 x 1020 kJ/mol
O 3.69 x 1013 kJ/mol
O 1.23 x 103 kJ/mol​

Answer 1

Answer:

The mass defect for an isotope was found to be 0.410 amu/atom. Calculate the binding energy in kJ/mol of atoms. (1 J = 1 kg m2/s2): (a) 3.69 x 1010 kJ/mol: (b) 1.23 x 1020 kJ/mol: (c) 3.69 x ... Calculate the binding energy per nucleon (in units of MeV) for 9Be, for which the ... (a) 4He: (b) 16O: (c) 32S: (d) 55Mn: (e) 238U. 6.

Answer 2

Answer:

The binding energy in KJ/mol of atoms is 3.69×$10^1^0$

Explanation:

Binding energy is usually described because the smallest quantity of energy is required to get rid of a particle from a machine of particles. In different words, it's far from the energy this is used to split a machine of particles into unmarried units. We take a look at approximately binding energy broadly speaking in atomic physics and chemistry in addition to condensed depending on physics. In nuclear physics, the binding energy period is used to explain the separation of energy.

Binding energy is important to cut up subatomic particles in atomic nuclei or the nucleus of an atom into its additives namely: neutrons and protons or together called the nucleons. The binding energy of nuclei is a high-quality fee due to the fact each nucleus wants net energy to isolate them into each neutron and proton. Binding energy is likewise relevant to atoms and ions sure collectively in crystals.

Mass defect is calculated by the difference between the atomic mass and expected by the combined masses of its protons.

Δm = 0.41 amu

1 amu = 1.67 × $10^-^2^7$Kg

binding energy = Δm.c^2

BE = 0.41 × 1.67 × $10^-^2^7$ × (3×$10^8$)^2

BE =  3.69×$10^1^0$KJ / mol

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