Question

1. 212y5 is a multiple of 3 and 11. Find the value of y. 2. 1z3z6 is divisible by 11. Find the value of z.

Answer 1

Answer:

y =5 or 8 or 2 as adding these gives only solution for divisibility of 3

substituing each value and dividing it by 11 we get that only 8 can be substituted to make the number divisible by 11