Question

1. 22x + 25y =304 ; 25x +22y =307
2. 21x + 47y = 110. ; 47x + 21y =162
Solve these...

Answer 1

Given:-

1.)

➜22x+25y=304–(1)

➜25x+22y=307–(2)

2.)

➜21x+47y=110–(1)

➜47x+21y=162–(2)

$\rule{200}{1}$

To Find:-

➜The Value of x and y?

$\rule{200}{1}$

AnsWer:-

1.)↓

✪Subtracting Eq-(1)&(2)✪

↝3x-3y=3—[÷by 3]

↝x-y=1–(3)

✪Adding Eq-(1)&(2)✪

↝47x+47y=611—[÷by 47]

↝x+y=13–(4)

▼Subtracting (3)&(4)▼

↝-2y=-12

↝y=$\frac{\cancel{-12}}{\cancel{-2}}$

☞y=6–(5)

•Using (5)in (3)•

↝x-6=1

↝x=6+1

☞x=7

$\rule{200}{1}$

2.)↓

✪Subtracting Eq-(1)&(2)✪

↝26x-26y=52—[÷by 26]

↝x-y=2–(3)

✪Adding Eq-(1)&(2)✪

↝x+y=4–(4)

▼Subtracting (3)&(4)▼

↝2y=2

↝y=$\frac{\cancel{2}}{\cancel{2}}$

☞y=1–(5)

•Using (5)in(3)•

↝x-1=2

↝x=2+1

☞x=3

$\rule{200}{2}$

Answer 2

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QUESTION :

1. 22x + 25y =304 ; 25x +22y =307

2. 21x + 47y = 110. ; 47x + 21y =162

Solve these...

SOLUTION :

We have the following equations :

• PART I :

$22x + 25 y = 304 \: , \: 25x + 22y = 307$

$&#8658 Sum \: = \: 47 x + 47 y = 611$

$&#8658 x + y = 13$

$&#8658 Difference \: = \:-3 x + 3y = -3$

$&#8658 x - y = 1$

So,

X = 7, y = 6

The values of X = 7 and y = 6 satisfies the first set of equations.

• PART II :

$21 x + 47 y = 110 \: , 47x + 21 y = 162$

$&#8658 Sum \: = \: 68 x + 68 y = 272$

$&#8658 x + y = 4$

$&#8658 Difference \: = \: -26 x + 26 y = -52$

$&#8658 x - y = 2$

So,

X = 3 , y = 1

The values of X = 3 and y = 1 satisfies the second set of equations.