Question

1.2373 (bar) 9th class cbse

Answer 1

Let x =1.2373 (bar)
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As there are 4 numbers under bar, multiply by 10000.
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10000 × x = 10000 ×1.2373

10000x = 12373.2373 (bar)

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Subtract x from both sides,

10000x = 12373. 2373 (bar)
       -  x =       - 1. 2373  (bar)
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9999x = 12372  [bar will cancel]

x = $\frac{12372}{9999}$
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Then,

1.2373 (bar)  in rationalizing form is $\frac{12372}{9999}$

i hope this will help you

-by ABHAY

Answer 2

Hi ,

Let x = 1.237333.....---( 1 )

Multiply equation ( 1 ) with 1000,

1000x = 1237.333....---( 2 )

Multiply equation ( 2 ) with 10 ,

10000x = 12373.333....( 3 )

Subtract ( 2 ) from ( 3 ) , we get

990x = 11136

x = 11136/990

x = 5568/495

Therefore ,

x = 1.2373... = 5568/495

I hope this helps you.

: )