Question

1.24 g P'is present in. 2.2 g of...option( 1.) P2S4.(2.) P2S2.(3.)P4S3.(4.)PS2

Answer 1

P = Phosphorus

S = Sulphur 

P = 31, S = 32


( 1.) P2S4 = 2x31 + 32x4 = 190

Mass of P = 62

2.2 g of P2S4 contain = (2.2x62)/190 = 0.718g of P




(2.) P2S2= 2x31 + 32x2 = 126
Mass of P = 62

2.2 g of P2S2 contain = (2.2x62)/126 = 1.08g of P




(3.) P4S3 = 4x31 + 32x3 = 220

Mass of P = 124

2.2 g of P4S3 contain = (2.2x124)/220 = 1.24g of P




(4.)P S2 =  1x31 + 32x2 = 95

Mass of P = 31

2.2 g of PS2 contain = (2.2x31)/95 of = 0.7118g P





The correct answer is: 


(3.) P4S3 


2.2 g of P4S3 contain 1.24g of P

Answer 2

Answer:

Step-by-step explanation:

P = Phosphorus

S = Sulphur

P = 31, S = 32

( 1.) P2S4 = 2x31 + 32x4 = 190

Mass of P = 62

2.2 g of P2S4 contain = (2.2x62)/190 = 0.718g of P

(2.) P2S2= 2x31 + 32x2 = 126

Mass of P = 62

2.2 g of P2S2 contain = (2.2x62)/126 = 1.08g of P

(3.) P4S3 = 4x31 + 32x3 = 220

Mass of P = 124

2.2 g of P4S3 contain = (2.2x124)/220 = 1.24g of P

(4.)P S2 = 1x31 + 32x2 = 95

Mass of P = 31

2.2 g of PS2 contain = (2.2x31)/95 of = 0.7118g P

The correct answer is:

(3.) P4S3

2.2 g of P4S3 contain 1.24g of P