Question

1.25×10^18 electrons are passed from one end to another end of conductor in 10 sec. find the current flowing through the conductor.

Answer 1

1.25 × 10^18 electrons pass through a cross sectional area of the conductor in 10 seconds.

To find:

Current flowing through the conductor.

Calculation:

First , we need to find out the total charge passing through the cross sectional area of the conductor.

Charge on 1 electron = 1.6 × 10^(-19) C

$charge =( 1.25 \times {10}^{18}) \times (1.6 \times {10}^{ - 19} )$

$= > charge = 2 \times {10}^{ - 1}$

$= > charge = 0.2 \: coulomb$

Current is defined as the rate of charge flow.

$current = \dfrac{charge}{time}$

$= > current = \dfrac{0.2}{10}$

$= > current = 0.02 \: amp$

So final answer is :

Current is 0.02 Ampere.

Answer 2

Given :

• Number of electrons (n) = 1.25 * 10^18
• Time (t) = 10 s

To Find :

• Current Flowing in the conductor

Solution :

For finding current moving in the conductor, we first have to find the charge of the circuit. And then we can find current flowing in conductor.

$\underbrace{\sf{Charge \: on \: Conductor}}$

• Charge of electron (e) = 1.6 * 10^-19 C
• number of electrons (n) = 1.25 * 10^18 electrons

$\implies \sf{Q \: = \: ne} \\ \\ \implies \sf{Q \: = \: (1.6 \: \times \: 10^{18} ) \: \times \: (1.25 \: \times \: 10^{-19})} \\ \\ \implies \sf{Q \: = \: 2 \: \times \: 10^{18 \: - \: 19}} \\ \\ \implies \sf{Q \: = \: 2 \: \times \: 10^{-1}} \\ \\ \implies \sf{Q \: = \: 0.2 \: C}$

$\therefore$ Charge of the conductor is 0.2 C

_______________________________

$\underbrace{\sf{Current \: flowing \: in \: Conductor}}$

$\implies \sf{I \: = \: \dfrac{Q}{t}} \\ \\ \implies \sf{I \: = \: \dfrac{0.2}{10}} \\ \\ \implies \sf{I \: = \: 0.02 \: A}$

$\therefore$ Current Flowing in circuit is 0.02 Ampere