1.25 gram of solid dibasic acid is completely neutralized with 25 ml and 0.25 molar barium hydroxide the molecular mass if the acid is
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dibasic=> acids are those which have two atoms of hydrogen firstly i am solving your question i will tell u one thing what dibasic acids are dude
dibasic acid = (acid)H2 reacts with 25 ml of 0.25molar barium hydroxide
now,
25 ml of 0.25 molar barium hydroxide ba(oH)2 which means 0.025L *1/0.25 = 0.01 moles of barium hydroxide
which means 0.1mole of ba(OH)2 will completely nutralize the di basic acid dude
so number of moles of dibasic acid of (acid )H2= 0.01/2 = 0.005 moles mass of 0.005moles of (acid)H2=1.25 gm
so ,
one mole of (acid)h2= 1.25/0.005 = 1250/5= 250 gm this is the correct method dude ask any doubt in comment box if u have good luck study hard ^_^
dibasic acid = (acid)H2 reacts with 25 ml of 0.25molar barium hydroxide
now,
25 ml of 0.25 molar barium hydroxide ba(oH)2 which means 0.025L *1/0.25 = 0.01 moles of barium hydroxide
which means 0.1mole of ba(OH)2 will completely nutralize the di basic acid dude
so number of moles of dibasic acid of (acid )H2= 0.01/2 = 0.005 moles mass of 0.005moles of (acid)H2=1.25 gm
so ,
one mole of (acid)h2= 1.25/0.005 = 1250/5= 250 gm this is the correct method dude ask any doubt in comment box if u have good luck study hard ^_^
itish1:
ihave understand till molarmass=1.25/0.00625
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