Question

(1.25)^x+1 =(125)^-2 find the value of "x"

Answer 1

Answer:

ACCORDING TO THE QUESTION :-

$= > {(1.25)}^{x + 1} = {(125)}^{ - 2} \\ \\ = > {(1.25)}^{x + 1} = {(1.25)}^{ - 2} {(100)}^{ - 2} \\ \\ = > {(1.25)}^{x + 3} = {(10)}^{ - 4} \\ \\ = > x + 3 = { {(1.25)}^{(10)} }^{ - 4} \\ \\ = > x = {(1.25)}^{ {(10)}^{ - 4} } - 3$