Question

1/25x^2-1/36y^2 factorize ​

Answer 1

The factors of $\frac{1}{25}x^{2}-\frac{1}{36}y^{2}$ are $(\frac{1}{5}x+\frac{1}{6}y)(\frac{1}{5}x-\frac{1}{6}y)$.

Step-by-step explanation:

The value of (a + b)(a - b) is:

$(a + b)(a - b)=a^{2}-b^{2}$

Use this property to determine the factors of the expression $\frac{1}{25}x^{2}-\frac{1}{36}y^{2}$ as follows:

$\frac{1}{25}x^{2}-\frac{1}{36}y^{2}=(\frac{1}{5}x)^{2}-(\frac{1}{6}y)^{2}$

                   $=(\frac{1}{5}x+\frac{1}{6}y)(\frac{1}{5}x-\frac{1}{6}y)$

Thus, the factors of $\frac{1}{25}x^{2}-\frac{1}{36}y^{2}$ are $(\frac{1}{5}x+\frac{1}{6}y)(\frac{1}{5}x-\frac{1}{6}y)$.

Answer 2

$\frac{1}{25x ^{2} } - \frac{1}{36y ^{2} } \\ ( \frac{1}{5x} ) ^{2} - (\frac{1}{6y} ) ^{2} \\ (\frac{1}{5x} + \frac{1}{6y} )(\frac{1}{5x} - \frac{1}{6y} )$

Using identity a²-b²= (a+b)(a-b)