Question

1) 26.4 % Carbon 3.3 % Hydrogen 70.3 % Oxygen Molar Mass: 91.0 g/mol.find empirical formula​

Answer 1

Answer:

c= 26.4/12= 2.2

H = 3.3/1 = 3.3

O = 70.3/16= 4.4

simple whole no.ratio of C = 2.2/2.2= 1

H = 3.3/2.2 = 1.5 nearly 2

O = 4.4/2.2= 2

empirical formula = CH2O2