Chemistry, asked by neymbang, 2 days ago

1.26 gms of oxalic acid is present in 250ml of solution calculate the strength of solution in normality and molality

Answers

Answered by killerdeath5689

0

Explanation:

Molecule of oxalic acid H2C2O4.2H2O=126g/mol

1.26g is dissolved in 250ML

→5.04g is dissolved in 1000ML

Normality =Mass of solute/dn3 solution Equivalent weight

= 5.04/63

=0.08N

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