Question

1.26g of a dibasic acid were dissolved in water and the solution made upto 200ml. 20ml of this solution was completely neutralised by 10ml of N/5 NaOH solution. The molecular mass of the acid is

Answer 1

Explanation:

Answer

As we know that,

Normality =

equivalent mass

mass of solute

×volume(L)

Equivalent mass =

n−factor

molecular mass

[ Here n factor is 2 as it is dibasic acid ]

Normality of dibasic acid =

x

1.26

×

200

1000

N

1

=

x

6.3

⇒ (x=eq.mass)

By the formula,

N

1

V

1

=N

2

V

2

x

6.3

×20=10×

5

1

2

6.3

×20=x ⇒ x=68

Equivalent mass = 63

and molecular mass=63×2=126

(2 is n−factor)

Answer 2

Answer:

Equivalent mass = 63.

Molecular mass = 63×2

= 126.

2 is n-factor.

Explanation:

I hope it will be helpfull.

Plese mark me as a brainlist.

THANK YOU....