Question

1.26g of acetic acid is dissolved in 500ml of water,calculate molarity

Answer 1

HEYA GM ❤

★ MOLECULAR MASS OF ACETIC ACID = 60

» MOLARITY (M) = Weight / Molecular mass × Volume(L)

» M = 1.26 / 60 × 0.5L

» M = 1.26 / 30 = 0.042 Moles / L

TQ ❤ ❤

Answer 2

$\huge\underline\purple{\sf Answer}$

AIM:: To calculate The Molarity By using above information .

GIVEN :

weight of solute (CH3 COOH) = 1.26g

Molecular weight of solute = 60

Volume of solvent = 500ml

Molarity = Wt of solute/ Molecular weight × 1 / Volume in litre .

❇Molarity = 1.26 / 60 × 0.5 L

❇M = 1.26/ 30

❇M = 0.042 mol/L

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