Question

1-27z^3 factorise the following expression​

Answer 1

Answer:

1 - 27z³ = (1-3z)(1+3z+9z²)

Step-by-step explanation:

Given expression 1 - 27z³

= 1³ - (3z)³

= (1-3z)[1²+1×3z+(3z)²]

/* By algebraic identity:

a³-b³ = (a-b)(a²+ab+b²) */

=(1-3z)(1+3z+9z²)

Therefore,

1 - 27z³ = (1-3z)(1+3z+9z²)

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Answer 2

Answer:

=1-27z^3

=(1)^3-(3z)^3

=(1-3z)(1+3z+9z^2)