1-27z^3 factorise the following expression
Answers
Answered by
2
Answer:
1 - 27z³ = (1-3z)(1+3z+9z²)
Step-by-step explanation:
Given expression 1 - 27z³
= 1³ - (3z)³
= (1-3z)[1²+1×3z+(3z)²]
/* By algebraic identity:
a³-b³ = (a-b)(a²+ab+b²) */
=(1-3z)(1+3z+9z²)
Therefore,
1 - 27z³ = (1-3z)(1+3z+9z²)
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Answered by
1
Answer:
=1-27z^3
=(1)^3-(3z)^3
=(1-3z)(1+3z+9z^2)
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