Question

(1) 28
(2) 15 33, 7(3) 13
) 16
47. What must be added to the numbers 6, 10, 14 and 22 so that they are in proportion?
(1) 1
(2) 3
(4) 4
(3) 2​

Answer 1

Answer:

3)2

Step-by-step explanation:

6+2=8

10+2=12

14+2=16

22+2=24

Answer 2

Answer:

2

Step-by-step explanation:

Let the number ' x ' should be added

to the given numbers so that they

are in proportional.

Therefore ,

( 6 + x ) , ( 10 + x ) , ( 14 + x ) , ( 22 + x )

are in proportion .

Product of extrems = product of

means

( 6 + x ) ( 22 + x ) = ( 10 + x ) ( 14 + x )

132 + 28x + x² = 140 + 24x + x²

28x - 24x = 140 - 132

4x = 8

x = 8/2

x = 2

Therefore ,

Required number = x = 2

I hope this helps you.

:)