1/√28 ka man dashamav ke no tak
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rearranging the terms in the form (a-b)^2 = (a^2+b^2-2*a*b)
(28-10*sqrt(3))
=25+3-2*5*sqrt(3)
=(5-sqrt(3))^2
=A (say)
(7+4*sqrt(3))
=4+3+2*2*sqrt(3)
=(2+sqrt(3))^2
=B (say)
Now
Y = (28 - 10*3^1/2) ^1/2 - (7 +4*3^1/2) ^ -1/2
= sqrt (A) - 1/sqrt(B)
= (5-sqrt(3))- 1/(2+sqrt(3))
= (5-sqrt(3))- (2-sqrt(3))
= 3
(28-10*sqrt(3))
=25+3-2*5*sqrt(3)
=(5-sqrt(3))^2
=A (say)
(7+4*sqrt(3))
=4+3+2*2*sqrt(3)
=(2+sqrt(3))^2
=B (say)
Now
Y = (28 - 10*3^1/2) ^1/2 - (7 +4*3^1/2) ^ -1/2
= sqrt (A) - 1/sqrt(B)
= (5-sqrt(3))- 1/(2+sqrt(3))
= (5-sqrt(3))- (2-sqrt(3))
= 3
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