Question

1+2ab-( a square+b square)

Answer 1

$Given \: 1 + 2ab - ( a^{2} + b^{2} ) \\= 1 + 2ab - a^{2} - b^{2} \\= 1 - ( a^{2} + b^{2} - 2ab ) \}= 1^{2} - (a-b)^{2}\\= [ 1 + ( a - b ) ] [ 1 - ( a + b ) ] \\= ( 1 + a - b )( 1 - a - b )$

Therefore.,

$\red { 1 + 2ab - ( a^{2} + b^{2} )} \\\green { = </p><p>( 1 + a - b )( 1 - a - b )}$

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