(1+2i)³/(1+i)(2-i), express in the form (a+ib)...
plz help me frnds
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thats ur answer.......
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(i+2)^3=1-8i+6i-12
(i+2)^3/(1+i)(2-i)=-(2i+11)/(i+3) [i*i=-1,i*i*i=-i]
=-(2i+11)(i-3)/(i+3)(i-3)
=-(5i-35)/-10
= (i-7)/2
(i+2)^3/(1+i)(2-i)=-(2i+11)/(i+3) [i*i=-1,i*i*i=-i]
=-(2i+11)(i-3)/(i+3)(i-3)
=-(5i-35)/-10
= (i-7)/2
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