Math, asked by UmarMansoor, 1 year ago

1+2log(x+2)5=log 5(x+2)

Answers

Answered by saurabhsinghbihari
29
I hope this answer would be helpful for you
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saurabhsinghbihari: most welcome
Answered by tardymanchester
13

Answer:

The value of x is 23,-1,8.

Step-by-step explanation:

Given : 1+2\log_{(x+2)}5=\log_5(x+2)

To find : The value of x?

Solution :

1+2\log_{(x+2)}5=\log_5(x+2)

1+\frac{2}{\log_5(x+2)}=\log_5(x+2)

\log_5(x+2)+2=(\log_5(x+2))^2

Let  \log_5(x+2)=t

Now, the equation became

t+2=t^2

t^2-t-2=0

(t+1)(t-2)

t=-1, t=2

Substitute back we get,

\log_5(x+2)=t

When t=-1

\log_5(x+2)=-1

x+2=\frac{1}{5}

x=-1,8

When t=2

\log_5(x+2)=2

x+2=25

x=23

Therefore, The value of x is 23,-1,8.

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