1+2log2 base x*log(10-x) base 4=2/log x base 4
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Some of the basic results used here:
logab=logcblogcalogab=logcblogca
logax=y⟹x=aylogax=y⟹x=ay
logab=blogalogab=bloga
Now focusing on the problem,
log2x+log4x=2log2x+log4x=2
∴logxlog2+logxlog4=2∴logxlog2+logxlog4=2
∴logxlog2+logx2log2=2∴logxlog2+logx2log2=2
∴logxlog2(1+12)=2∴logxlog2(1+12)=2
∴32×logxlog2=2∴32×logxlog2=2
∴log2x=43∴log2x=43
∴x=2
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here the answer is in picture I hope you like it
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