Question

1/2Mole oxygen react with Al and gives Al2O3 ,what is the weight of Al in reaction

Answer 1

The balanced reaction is 4Al + 3O2 =  2Al2O3

​3moles of O2 requires 4 moles of Al
0.5 moles of O2 requires =  4 X 0.5/3 = 2/3 moles of Al

Mass of 2/3 mol of Al = 2/3 mol  X 27g/mol = 18 g

Answer 2

2/3 Al + 1/2 02 --> 1/3 Al2O3

This will be the balanced equation for the question.

Now clearly if 1/2 moles of oxygen is used then 2/3 moles of aluminium is used.

1 mole has 27g of Aluminium

2/3 moles of aluminium has 27*(2/3)

The total weight of aluminium is 18grams.



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