Question

(1/2pq-3/2q)×(pq-q)=?
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Answer 1

Step-by-step explanation:

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Answer 2

$(\frac{1}{2}pq-\frac{3}{2}q)\times (pq-q)=\frac{1}{2}p^2q^2-2pq^2-\frac{3}{2}q^2$

Step-by-step explanation:

Given : Expression $(\frac{1}{2}pq-\frac{3}{2}q)\times (pq-q)$

To find : Solve the expression ?

Solution :

Expression $(\frac{1}{2}pq-\frac{3}{2}q)\times (pq-q)$

Applying distributive property, $a(b+c)=ab+ac$

Re-write the expression as,

$=\frac{1}{2}pq\times (pq-q)-\frac{3}{2}q(pq-q)$

$=\frac{1}{2}pq\times pq-\frac{1}{2}pq\times q-\frac{3}{2}q\times pq-\frac{3}{2}q\times q$

$=\frac{1}{2}p^2q^2-\frac{1}{2}pq^2-\frac{3}{2}pq^2-\frac{3}{2}q^2$

$=\frac{1}{2}p^2q^2-pq^2(\frac{1}{2}+\frac{3}{2})-\frac{3}{2}q^2$

$=\frac{1}{2}p^2q^2-pq^2(\frac{4}{2})-\frac{3}{2}q^2$

$=\frac{1}{2}p^2q^2-2pq^2-\frac{3}{2}q^2$

Therefore, $(\frac{1}{2}pq-\frac{3}{2}q)\times (pq-q)=\frac{1}{2}p^2q^2-2pq^2-\frac{3}{2}q^2$

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