1+2q+q®2. factorise step by step
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• 1 + 2q + q²
• Rearranging the terms, we get,
= q² + 2q + 1
• Now, by midterm split method,
= q² + 2q + 1
= q² + q + q + 1
= q (q + 1) + 1 (q + 1)
= (q + 1)(q + 1)
= (q + 1)²
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• 1 + 2q + q²
• Rearranging the terms, we get,
= q² + 2q + 1
= [ (q)² + (2 × q × 1) + (1)² ]
[] Using identity : a² + 2ab + b² = (a + b)²,
= (q + 1)²
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Thank you.. ;-)
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