Question

(1÷
2Sin A Cos A - SinAX SinA- Cos AX CosA)
Proof this is equal to (1 + SeeAcosecA)
​

Answer 1

Step-by-step explanation:

Bro I think your question is wrong from some point.

Because, See this --

LHS =

( 1 ÷ 2sinA cosA - sinA × sinA - cosA × cos A )

= 1 ÷ 2sinAcosA - sin^2A - cos^2A

= 1 ÷ - ( 2sinAcosA + sin^2A - cos^2A )

= -1 ÷ 2sinAcosA + sin^2A - cos^2A

RHS =

= 1 ÷ secA cosecA

= 1 ÷ ( 1 ÷ tanA × 1 ÷ sin A )

= sinA ÷ ( cosA ÷ sinA )

= sin^2A ÷ cosA

-✌️✌️ Please see I may be wrong .

But if you solve this problem please show me the solution .

And if you are preparing for exams , So good luck ☺️☺️☺️