Question

1-2sin square (45° - 3A) = sin 6A​

Answer 1

Answer:

we know that

$1 - 2 \sin {}^{2} ( \alpha ) = \cos(2 \alpha )$

then,

$\cos2(45 - 3 \alpha ) = \cos(90 - 6 \alpha ) = \sin(6 \alpha )$