Question

((1-2sin2A)^2)/cos4A-sin4A=2cos2A-1

Answer 1

Thank you for asking this question. Here is your answer:

(1-2 sin² A)² / cos⁴A sin² A

= (cos2A)²/ (cos² A -sin² A) (cos² A + sin² A)

= (cos² A - sin² A )² / (cos² A - sin² A) (cos² A + sin² A)

(cos² A - sin² A)

(cos² A - ( 1 -cos²A))

= 2 cos² A - 1

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