Math, asked by mataleshmahato, 10 months ago

√(1-2sinA.cosA) =cosA-sinA

Answers

Answered by FeluMitter

8

Answer:

Step-by-step explanation:

$\sqrt{1-2sinAcosA}=\sqrt{sin^2A+cos^2A-2sinAcosA}=\sqrt{(sinA-cosA)^2}$

$sinA-cosA$ (or) $cosA-sinA$

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