Math, asked by ak2410855, 1 year ago

1+2tan^2A/cos^2A=tan^4A+sec^4A

Answers

Answered by smartAbhishek11

1

Dear student
We have,sec2A(sec2A−2)+1=(1+tan2A)(1+tan2A−2)+1=(1+tan2A)(tan2A−1)+1=tan4A−1+1=tan4A
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