1/2x+1/3y=2
1/3x+1/2y=13/6solve in elimination method
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Answer:
let 1/x=a and 1/y =b
we get
a/2+ b/3= 2
3a+2b= 12 (equation 1)
a/3+b/2=13/6
2a+3b= 13 (equation 2)
by simplifying equation 1 and equation 2
we get
5a= 10
a= 10/5
a= 2
by putting value of a in equation 1
3a+2b= 12
3(2)+ 2b=12
2b= 12-6
b= 6/2
b=3
,now,
we have
1/x=a
1/x= 2
x= 1/2
and
1/y= b
1/y= 3
y= 1/3
hence
the values of
x=1/2 and y= 1/3
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