Question

(1)2x^2-x+1/8=0
(2) 2x^2+x-6=0 find roots of given quadratic equation by factorisation​

Answer 1

Answer:

roots of equations

(1) 1/4 and 1/4

(2) 3/2 . -2

Step-by-step explanation:

(1) 2x² - x + 1/8 = 0

(16x² - 8x + 1)8 = 0

16x² - 8x + 1 = 0 × 8

16x² - 8x + 1 = 0

16x² - (4 + 4)x + 1 = 0

16x² - 4x - 4x + 1 = 0

4x(4x - 1).-1(4x - 1) = 0

(4x - 1)(4x - 1) = 0

4x - 1 = 0 . 4x - 1 = 0

4x = 1 . 4x = 1

x = 1/4 . x = 1/4

(2) 2x² + x - 6 = 0

2x² + (4 - 3)x - 6 = 0

2x² + 4x - 3x - 6 = 0

2x(x + 2).-3(x + 2) = 0

(2x - 3)(x + 2) = 0

2x - 3 = 0 . x + 2 = 0

2x = 3 . x = -2

x = 3/2 . x = -2