Question

1 + 2x
2x
If f(x)= log
then f
1- 2x
1+ 4x​

Answer 1

Answer:

One way of solving is:

f(x) = log(1+x/1-x)

f(x) = log(1+x) - log(1-x)

To find the given function replace x with (2x/1+x^2).

f(2x/1+x^2) = log(1+(2x/1+x^2)) - log(1-(2x/1+x^2))

f(2x/1+x^2) = log((x^2+1+2x)/(1+x^2))-log((x^2+1-2x)/(1+x^2))

On simplifying the above equation we get,

f(2x/1+x^2) = log((x+1)^2/(x-1)^2).

This can be written as 2*log((x+1)/(x-1)).

Hope this helps :).

Step-by-step explanation:

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Answer 2

Answer:

x can be either 1 or 3. hope it helps