Question

1/2x-3+1/x-5=11/9 quadratic equations​

Answer 1

Answer:

$\frac{1}{2} x - 3 + \frac{1}{x} - 5 = \frac{11}{9}$

$= > \frac{1}{2} x - \frac{1}{x} - 8 = \frac{11}{9}$

$= > \frac{1}{2} x - \frac{1}{x} = \frac{11}{9} - 8$

$= > \frac{1}{2} x - \frac{1}{x} = \frac{11 - 72}{9}$

$= > \frac{1}{2} x - \frac{1}{x} = \frac{ - 61}{9}$

$= > x - \frac{1}{x} = \frac{ - 61}{9} \times \frac{2}{1}$

$= > x - \frac{1}{x} = \frac{ - 122}{9}$

$= > x - x = \frac{ - 122}{9}$

$= > x = \frac{ - 122}{9}$

Answer 2

$\huge\underbrace\green{Answer}$

21x−3+x1−5=911

= > \frac{1}{2} x - \frac{1}{x} - 8 = \frac{11}{9}=>21x−x1−8=911

= > \frac{1}{2} x - \frac{1}{x} = \frac{11}{9} - 8=>21x−x1=911−8

= > \frac{1}{2} x - \frac{1}{x} = \frac{11 - 72}{9}=>21x−x1=911−72

= > \frac{1}{2} x - \frac{1}{x} = \frac{ - 61}{9}=>21x−x1=9−61

= > x - \frac{1}{x} = \frac{ - 61}{9} \times \frac{2}{1}=>x−x1=9−61×12

= > x - \frac{1}{x} = \frac{ - 122}{9}=>x−x1=9−122

= > x - x = \frac{ - 122}{9}=>x−x=9−122

= > x = \frac{ - 122}{9}=>x=9−122