Question

1 : 2x+3/3+x= 3/2
Linear equations and it's verification process

Answer 1

Answer :

x = 3

Step-by-step explanation :

$\sf \dfrac{2x + 3}{3 + x}=\dfrac{3}{2} \\ \\ \bf on \: cross \: multiplying : \\ \\ \sf 2(2x+3) = 3(3+x) \\ \\ \sf 4x + 6 = 9 + 3x \\ \\ \sf 4x - 3x = 9 - 6 \\ \\ \underline{ \boxed{ \bf{x = 3}}}$

Verification :

Putting the value of x , we get ;

$\sf \dfrac{2x + 3}{3 + x} = \frac{3}{2} \\ \\ \sf \frac{2 \times 3 + 3}{3 + 3} = \frac{3}{2} \\ \\ \sf \frac{6 + 3}{6} = \frac{3}{2} \\ \\ \sf \frac{9}{6} = \frac{3}{2} \\ \\ \sf \frac{3}{2} = \frac{3}{2} \\ \\ \therefore \bf LHS = RHS$

Hence, the value of x is 3.