Question

1 2x-3y +13=0
3x - 2y + 12 = 0​

Answer 1

The given pair of linear equations is

2x−2y+13=0 or

3x−2y+12=0

On comparing the given equations with standard form of pair of linear equations i.e a

1

x+b

1

y+c

1

=0 and a

2

x+b

2

y+c

2

=0, we get

a

1

=2,b

1

=−3 and c

1

=13

and a

2

=3,b

2

=−2 and c

2

=12

a

2

a

1

=

3

2

,

b

2

b

1

=

−2

−3

=

2

3

and

c

2

c

1

=

12

13

∴

a

2

a

1



=

b

2

b

1



=

c

2

c

1

The lines representing the given pair of linear equations will intersect at a point.

Now, table for 2x−2y+13=0 or y=

3

2x+13

Now, table for 3x−2y+12=0 or y=

2

3x+12

Here, the lines intersecting at point B i.e. (-2, 3)

Hence, the unique solution is x=−2 and y=3.

dam sure with my answer

Answer 2

Answer:

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