Question

1-(2x+3y)-6(2x+3y)square ​

Answer 1

Answer:

Let (2x + 3y) = a

∴ (2x + 3y)2 = a2

∴ 1 – (2x + 3y) – 6 (2x + 3y)2

= 1 – a – 6a2

= 1 – 3a + 2a – 6a2

= 1(1 – 3a) + 2a (1 – 3a)

= 1(1 – 3a) (1 + 2a)

= [1 – 3(2x + 3y)] [1 + 2(2x + 3y)]

(Substituting the value of a)

= (1 – 6x – 9y) (1 + 4x + 6y)

Step-by-step explanation:

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