1. −2x ≤ 6 2. x−3 ≥ 2 3. x 2 > 3 4. − x 3 > 1 5. −2x ≤ −6 6. − x 2 < 3 7. −2x ≥ 6 8. x+5 > 3 9. x−5 > 2 10. x+1 ≥ 3 11. 2x < −4 12. −2x ≥ −4 13. x−5 ≥ 3 14. x 2 < −3
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Answer:
We have,
5(2x−7)−3(2x+3)≤0
⇒10x−35−6x−9≤0
⇒4x−44≤0⇒x≤11
And 2x+19≤6x+47
⇒2x−6x≤47−19
⇒−4x≤28⇒x≥−7
Thus using above two we have −7≤x≤11
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