1) (2x + 8y)^2
2) (3x + y + 2z )^2
Answers
Answered by
56
Heyaaa mate
The answer is:-
It can be solved using some algebraic identities.
They are -
1. (a + b )² = a² + 2ab + b²
2. (a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ac
Now,
According to question,
1. (2x + 8y)²
=> (2x)² + 2(2x)(8y) + (8y)²
=> 4x² + 32xy + 64y²
_____________________________
2. (3x + y + 2z)²
=> (3x)² + y² + (2z²) + 2 (2x) (y) + 2 (y) (2z) + 2 (2z) (3x)
=> 9x² + y² + 4z² + 4xy + 4xz + 12zx
Hope it helps you
Thanks
ance62:
nice answer
Answered by
12
Answer :
1) 4x² + 32 xy + 64 y²
2) 9x² + y² + 4z² + 4xy + 4yz + 12zx.
Step-by-step explanation :
We will use some identities here ;
( a + b )² = a² + 2 ab + b²
( a + b + c )² = a² + b² + c² + 2ab + 2bc + 2ca.
Coming to the question ;
1) ( 2x + 8y )²
⇒ ( 2x )² + 2 * 2x * 8y + ( 8y )²
⇒ 4x² + 32 xy + 64 y²
Hence the answer is 4x² + 32 xy + 64 y².
2) ( 3x + y + 2z )²
⇒ ( 3x )² + y² + ( 2z )² + (2 * 3x * y) + (2 * y * 2z) + (2* 2z * 3x)
⇒ 9x² + y² + 4z² + 6xy + 4yz + 12zx.
Hence, the answer is
9x² + y² + 4z² + 6xy + 4yz + 12zx.
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