Question

1 + 2x + x^2. factorise it.....​

Answer 1

Answer:

x^2+2x+1=0

x^+x+x+1=0

x (x+1)+1 (x+1)

(x+1)(x+1)

Answer 2

Hey mate!!

here's your answer...

»To solve this first we have to rearrange it :

${x}^{2} + 2x + 1$

${x}^{2} + (1 x + 1x) + 1$

$x(x + 1) + 1(x + 1)$

$(x + 1)(x + 1)$

so value of x are :-

x+1=0 ________(i)

so, x=-1

and

x+1=0 ________(ii)

so, x=-1

$<marquee>★Hope it will be helpful for you ☺★$