Question

1/2x+y=1 and 1/3x-7y=4 value of x and y​

Answer 1

Answer:

The solution is

$x=\frac{29}{68}\;\;and\;\;y=\frac{10}{68}$

Step-by-step explanation:

Given equations are

$\frac{1}{2x+y}=1$

$\frac{1}{3x-7y}=4$

These can be written as

$2x+y=1$.....................(1)

$3x-7y=\frac{1}{4}$............(2)

$14x+7y=7$.....................(1)*4

$3x-7y=\frac{1}{4}$............(2)

$\implies\;17x=\frac{29}{4}$

$\implies\bf\;x=\frac{29}{68}$

$\text{put }x=\frac{29}{68}\text{ in (1), we get}$

$\frac{58}{68}+y=1$

$y=1-\frac{58}{68}$

$\implies\bf\;y=\frac{10}{68}$