Question

1. (2x4+ 7x-15 ) = (x+5)
2. (a 2 +21a -46) = (a - 2)
Q.13 in a quadrilateral ABCD, LA = 70, LB = 60 and LC = 120, find LD.
Q.14 find the value of x in the following quadrilateral
Q.15 the four angles of quadriteral are in the ratin​

Answer 1

Answer:

Let's solve your equation step-by-step.

2x4+7x−15=x+5

Step 1: Subtract x+5 from both sides.

2x4+7x−15−(x+5)=x+5−(x+5)

2x4+6x−20=0

Step 2: Factor left side of equation.

2(x+2)(x3−2x2+4x−5)=0

Step 3: Set factors equal to 0.

x+2=0 or x3−2x2+4x−5=0

x=−2 or x=1.525957

Answer:

x=−2 or x=1.525957

Step-by-step explanation:

2

Let's solve your equation step-by-step.

a(2)+21a−46=a−2

Step 1: Simplify both sides of the equation.

a(2)+21a−46=a−2

2a+21a+−46=a+−2

(2a+21a)+(−46)=a−2(Combine Like Terms)

23a+−46=a−2

23a−46=a−2

Step 2: Subtract a from both sides.

23a−46−a=a−2−a

22a−46=−2

Step 3: Add 46 to both sides.

22a−46+46=−2+46

22a=44

Step 4: Divide both sides by 22.

22a

22

=

44

22

a=2

Answer:

a=2