Question

(1-2xy/x2+y2) ÷ (x3-y3/x-y - 3xy)

Answer 1

Answer:

tell me about this question

Answer 2

Answer:

Correct answer is ( [( x-y ) ( 1 - 2xy ) ] - [ 3xy ( 1 - 2xy ) ] ] ) / ( x⁵ - y⁵ - x²y²(y - x))

Step-by-step explanation:

( 1-2xy / x²+y² ) ÷ ( x³-y³ / x-y-3xy )

= ( 1-2xy / x²+y² ) * (  x-y-3xy / x³-y³ )

=  ( x - y - 3xy - 2x²y + 2xy² + 6x²y² ) / ( x⁵ - x²y³ + x³y² - y⁵ )

= ( x - y ) - 3xy - 2xy( x-y ) + 6x²y² ] / ( x⁵ - x²y²(y - x) - y⁵ )

= ( [( x-y ) ( 1 - 2xy ) ] - [ 3xy ( 1 - 2xy ) ] ] ) / ( x⁵ - y⁵ - x²y²(y - x))

 

A common technique, PEMDAS has used for simplifying any mathematical equation.

PEMDAS means Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction.

Following the order is followed for solving the equation:

"Parentheses, Exponents, Multiplication and Division, and Addition and Subtraction".

that is why i did  (1-2xy / x²+y² ) and ( x-y-3xy / x³-y³ ) part first.